PHP将一个日期字符串转换成举例来说当前的天数
PHP将一个日期字符串转换成举例当前的天数输入为一个日期字符串,例如:2011-3-23
输出为举例当前的天数,例如:1
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代码为:
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public static function convertDateToLong($dateStr){ $checkPattern = "/^\d{4}(((-\d{1,2}){2})|((\.\d{1,2}){2})|((\/\d{1,2}){2}))$/"; $date = substr(trim($dateStr),0,strpos(trim($dateStr)," ")>0 ? strpos(trim($dateStr)," ") : strlen(trim($dateStr))); if(preg_match($checkPattern,$date)){ preg_match("/([-\/.])/",$date,$outer); $dilimeter = $outer[1]; list($year,$month,$day) = explode($dilimeter,$date); if(checkdate($month,$day,$year)){ $spsec = time()-mktime(0,0,0,$month,$day,$year); if($spsec < 0) throw new Exception("date can not be after today!!!"); $spday = floor($spsec/24/60/60); return $spday; } else{ throw new Exception("the date input is not a valid date"); } } else{ throw new Exception("the dateStr is wrong formatted!!!"); } }1 楼 bardo 2011-03-26 丢开有效性检验不说,这个代码绕的弯子太大了。算天数只要一代码:
$day=floor((time()-strtotime($date))/86400); 2 楼 liuzhiqiangruc 2011-03-30 bardo 写道丢开有效性检验不说,这个代码绕的弯子太大了。算天数只要一代码:
$day=floor((time()-strtotime($date))/86400);
确实,strtotime是可以的,多谢指点。:-) 3 楼 liuzhiqiangruc 2011-03-30 liuzhiqiangruc 写道bardo 写道丢开有效性检验不说,这个代码绕的弯子太大了。算天数只要一代码:
$day=floor((time()-strtotime($date))/86400);
确实,strtotime是可以的,多谢指点。:-)
而且,strtotime支持的日期格式很丰富,学习了。 4 楼 liuzhiqiangruc 2011-03-30 liuzhiqiangruc 写道liuzhiqiangruc 写道bardo 写道丢开有效性检验不说,这个代码绕的弯子太大了。算天数只要一代码:
$day=floor((time()-strtotime($date))/86400);
确实,strtotime是可以的,多谢指点。:-)
而且,strtotime支持的日期格式很丰富,学习了。
http://www.php.net/manual/en/datetime.formats.date.php
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