PHP判断是否连接上网络的方法

1

2

3

4

5

6

7

8

9

function varify_url($url){

$check = @fopen($url,"r");

if($check){

$status = true;

}else{

$status = false;

}

return $status;

}

1

2

3

4

5

6

$url = "http://www.baidu.com";

if(varify_url($url)){

echo "<div>Congratulation ! Your URL <a href=$url>$url</a> : is <b>valid </b></div>";

}else{

echo "<div>Error ! Your URL : <a href=$url>$url</a> is <b>invalid </b></div>";

}